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OpenStudy (anonymous):
Use the discriminant to determine the nature of the roots of 2x2 + 4x + 3 = 0.
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OpenStudy (anonymous):
@myko Can you help?
OpenStudy (anonymous):
discriminant of 2º order equation: \[ax ^{2} +bx +c =0\] is:\[D=b ^{2}-4ac\] depending on the sign of D you know what are the roots: D>0 : 2 distinct real roots D=0: 2 equal real roots D<0: no real roots
OpenStudy (anonymous):
in your case a=2, b=4, c=3
OpenStudy (anonymous):
So it's 2 equal real roots?
OpenStudy (anonymous):
That's what I'm getting @myko
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OpenStudy (anonymous):
D=16-4*2*3=16-24=-8 no real roots
OpenStudy (anonymous):
Oh, I see what I did wrong.
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