What are the possible number of positive, negative, and complex zeros of f(x) = –2x3 – 5x2 – 6x + 4 ?

Question

anonymous · Answer

i do not see this being able to be grouped so you shoudl use synthetic division

anonymous · Answer

What is the highest power of this polynomial???

anonymous · Answer

oh read it wong...

anonymous · Answer

Number of roots = Highest Power of the Polynomial...

anonymous · Answer

Oh im sorry i forgot exponent haha 2x^3 – 5x^2 – 6x + 4 and the highest power is 3

anonymous · Answer

So roots will also be equal to highest power...

anonymous · Answer

kk thank you :)

anonymous · Answer

-6-5(X)^2+6X+4=0
-5(X)^2+6X-2=0

Since the value of D is -4 that is -ve we will have two complex roots.
x=(-6+sqrt(D))/(2*(-5)) & x=(-6-sqrt(D))/(2*(-5)) that is
x=3/5-i/5 & x=3/5+i/5

anonymous · Answer

two complex roots, no positive or negative zeros