ssume that the terminal side of an angle of t radians in standard position lies in the given quadrant on the given straight line. Find sin (t), cos (t), tan (t).

Quadrant III; line through the origin parallel to: 4x - 9y = -8

Question

ssume that the terminal side of an angle of t radians in standard position lies in the given quadrant on the given straight line. Find sin (t), cos (t), tan (t).

Quadrant III; line through the origin parallel to: 4x - 9y = -8

anonymous · Answer

I'm guessing it is on 4x-9y=0

anonymous · Answer

hmm... idk why but it took me a while to understand this problem...

anonymous · Answer

do you know the equation of the line through the origin parallel to 4x - 9y = -8?

anonymous · Answer

Well, I know it has to be 4x-9y=0.  It's in Quadrant 3, so I think both (x,y) are going to be negative.

anonymous · Answer

I just really don't know where to go from there.

anonymous · Answer

Well, I know I need to find a radius, but I don't know what points to put in.

anonymous · Answer

ok... so here's a sketch of the line along with angle t....|dw:1340859603789:dw|