If f(3)-11, f' is continuous, then what's f(7) when:
have any idea?
well.... f(7) - f(3) is what the integral is.. but i don't know what that equals to.. do you just take the integral of the other side as well? so it's: f(7) - 11 = 20x? just you can't do that cuz there are two unknowns.
Hey @dpaInc will you please tell you did you zoom that letters that day?? And how to show cancelling of each term and if I want to show the factor by which I am cancelling that then can you please tell me how we do it??
yes.. you're basically using the FTC.... \(\large \int_a^b f'(t)dt=f(b)-f(a) \)
since f(7) - f(3) = 20, and f(3)=11... you can find f(7)
oh. so it is just plug in! haha, thanks! i just needed to see that..
yw...:)
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