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Solve for 5^(x+1)=25
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\[5^{x+1} = 5^2\] Can you now equate the exponents to find the value of x??
x+1=2 so x=1
Oh so the bases cancel, and you set the exponents equal to each other? then solve?
the bases don't cancel out its a mathematical intuition that since the bases are same the exponents have to be same
See, they are equal so, bases are same then there must be condition that exponents must be same that is why they are equal...
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Oh okay. Makes sense
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