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2x^4+4x^3+12x^2/2x explain
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so\[2x ^{4}+4x ^{3}+12x ^{2}\div2x\]
The entire equation will be divided by 2x then you will get 2x3+2x2+6x
wait, one thing, the 2x3? You are dividing by 2x
Yeah
wouldn't it be x2
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because the 1 is hidden and x2 is left
you divided all of the others by 2, 2x2 and 6x
2x4+4x3+12x2/2x 2x4/2x+4x3/2x+12x2/2x 2x3+2x2+6x
x3+2x2+6x
You have to divide all the terms by 2x and then you will get the answer
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Oh sorry it is x3 not 2x3
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