Question

2/x+2+1/x-2=13/21

Answer 1

Is your question \[\frac{2}{x+2}+\frac{1}{x-2}=\frac{13}{21}\]

Answer 2

yess

Answer 3

So you have to multiply each term by the common denominator and cancel: \[(21(x+2)(x-2))*\frac{2}{x+2}+(21(x+2)(x-2))*\frac{1}{x-2}=(21(x+2)(x-2))*\frac{13}{21}\]

Answer 4

ohhhhhhhh , lol that makes sense