if a bag has 40 red and blue marbles and a quarter of them are red,what is the probability of picking a blue marble?
Well 25% of the 40 marbles are red, and 25% of 40 is 10. 40-10=30, which means there are 30 marbles. That means the probability is 30/40, which when simplified is 3/4.
ahh thank you!i kept trying to do 60/40 for some reason
Oh okay yeah no prob. :)
and the fraction 3/5 cant be reduced correct?
Nope, nothing goes into 3 & 5 both besides 1.
thought so:)thank you very much for your help.
No problem :) If you need any other help I'll try my best to help :)
now i have a question like the marble one again but its three-quarters of them are red and it wants to know the probability of picking a blue marble
are there 40 total?
there are 40 marbles still.
40 red and blue.
K since we know a quarter of 40 is 10, that means 3 quarters is 30. There are 30 red and only 10 blue this time. That means probability is 10/40, but when simplified is 1/4.
what about the probability of picking a vowel from the word total?
it should be 2/6 correct?
K I'm gonna give you hints on this one and see if you can figure out. Hint: There are 5 letters in 'total', but only 2 vowels.
i meant 2/5
Yep :)
okayy ready for a hard question?
Lol I'll try my best to solve it :)
im sure you can you seem pretty smart:) a deck of cards is made up of 4 suits:clubs,diamonds,hearts,and spades.each suit has 13 cardds with this range:2,3,4,5,6,7,8,9,10,J,Q,K,and A. what is the probability of drawing a 7 or 8 from the deck of playing cards?
Okay so we see, there are 4 7's and 4 8's. This gives us 8/52. We can divide both by 2 to simplify it to 4/26. We can divide by 2 again, and get 2/13 as our probability.
i could get the 52 i just didnt know how many 7's and 8's.and thanks for helping i need to pass this quiz to pass my class its my last quiz and i graduate!
Omg I wish you best of luck :)
and it's Algebra I right?
it says its algebra 2 but i think it seems more like algebra 1
if you are trying to calculate the probability of rolling an even number on each die when rolling two dice,how large is the sample space? i keep getting 9 idk if thats right
Oh okay. I'm doing Algebra II virtual right now.
im good with all of my other online classes its just hard with math because it doesn't show me what i did wrong in the problem.
Idk what the sample space is so gonna figure out what that is quickly to try to help :)
im trying to google it:)
The sample space of an experiment is the set of all possible outcomes of that experiment.
Yuck. Die #1, Die #2 2,2 2,4 2,6 4,4 6,6 I would think there's only 5. Cause if you do 4,2 that's already on there and yeah.
this might help my choices for answers are A.6 B.12 C.36 D.18
Oh okay um..oh yeah forgot one. 2,2 2,4 2,6 4,4 6,6 4,6 There's 6 possibilities, A
okayy:) my next question is in a class of all girls,24 of the 30 have brown hair.what is the probability of randomly picking a girl with brown hair? dont i just do 24/30?
Yeah you just simplify if needed. and when you simplify you get 4/5.
i think i got this one wrong last time im so blonde. what is the probability of picking a consonant from A to Z?
Lol. Well there's 21 consonants, and 5 vowels. Your probability would be 21/26
duhhhh i put 22/26
which is more likely event, rolling a 4 on a die or a 5?
Both are the same :) They both got probability of 1/6.
okay good thats what i put:)ready for a stupid card question again?
lol sure.
a deck of cards is made up of suits:clubs,diamonds,hearts,and spades .each suit has 13 cards with this range:2,3,4,5,6,7,8,9,10,J,Q,K,and A. If you are trying to calculate the probability of getting an odd number when picking one card from a normal deal,what is the size of the sample space?
my choices for answers are A.13 B.26 C.52 D.5
I don't really know.
ill just guess:)
i guessed rightt
Lol congratz :)
haha thanks:)im doing my very last test and im finally done!
do you know how to find range?
That's the y-value. Not really. Anyways, g2g do a virtual quiz before I sleep so yeah, see you tomorrow :) Can't help any longer so yeah..:(
its okayy nightt!thank you for your help:)
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