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What is the value of the coefficient b when the quadratic equation y=(3x-5)(2x+3) is written in standard form? A: 19 B: 6 C: -15 D: -1
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C
@Pac1f1cIslander You are wrong unfortunately.
\[(3x - 5)(2x + 3) = 3x(2x + 3) - 5(2x + 3) = 6x^{2} + 9x - 10x - 15 = 6x^{2} - x - 15\]This is in the form:\[ax^{2} + bx + c\]Which is the b-term?
Um...
What's cut off should be \[6x^{2} - x - 15\]
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I really don't know ...
bx = -x What is b?
-1 ?
No keana, 6 Option B is 6
It's definitely -1.
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