Find the vertex, axis of symmetry, domain, and range of the graph of y = -2x2 - 6x + 1.
@keana have you studied Parabolas?
eh... @ash2326
you have to put the equation in vertex form: \[y=a(x-h)^2+k\]\[y=-2(x+\frac{3}{2})^2+\frac{11}{2}\]\[\] Vertex: (-\frac{3}{2}, \frac{11}{2}) domain is all real numbers
i agree with @ash2326 this a parabolas problem
for the axis of symmetry you use the -b/2a that come from the quadratic equation -b+- sqrt(b^2-4ac)/(2a)
a=-2 don't need to uses to find the axis of symmetric b=-6 c=1
Now uses the formula to find the axis of symmetry
@purplec16 what does "\frac{11}{2})" mean
It was unintentional it's latex rapping for when using the equation button in your post click equation put it in and see what happens :)
Vertex:\[(-\frac{3}{2}, \frac{11}{2})\]
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