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Solve the following inequality: \[3x^2(x-3)(x+3) ge 0\]
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\[3x^2(x-3)(x+3) \ge 0\]
dont you just equate each factor to 0? \[3x^2 \ge 0\] \[x-3 \ge 0\] \[x+3 \ge 0\] solve for x in each one
I thought your not allow to separate it?
Oh wait, never mind, that's set it equal to zero!... okay, thanks @lgbasallote
haha yes :)
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answer is \[\left| x \right| \ge 3\]
u were right wer not allow to separate it
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