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Mathematics 18 Online
OpenStudy (anonymous):

find the least common multiple 1/(x+2)^2 + 1/(x-2)^2 + 2/x^2-4 options: 1. (x+2)^3(x-2)^3 2. (x+ 2)^2(x- 2)^2 3. (x^2+2) (x^2-2)

OpenStudy (anonymous):

1

OpenStudy (anonymous):

are you sure

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I came up with answer number two. The denominator in the first term is (x+2)(x+2) The denominator in the second term is (x-2)(x-2) The denominator in the third term is a difference of square so it is (x+2)(x-2) So the lowest common multiple must include (x+2)(x+2)(x-2)(x-2)

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