Determine the symmetry of the function y=-x^3 (even, odd, or no symmetry) and explain how you arrived at your answer. Again, this wasn't in my lesson... Unless I missed it, trying to find it again...

Question

Determine the symmetry of the function y=-x^3  (even, odd, or no symmetry) and explain how you arrived at your answer. Again, this wasn't in my lesson... Unless I missed it, trying to find it again...

unklerhaukus · Answer

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anonymous · Answer

So it would be no sym. Right?

unklerhaukus · Answer

looks like it has rotational symmetry to me

unklerhaukus · Answer

a function $f(x)$ has odd symmetry iff $$f(-x)=-f(x)$$
even symmetry iff $$f(-x)=f(x)$$

unklerhaukus · Answer

$$y=f(x)=-x^3$$

$$f(-x)=-(-x)^3=$$