Question

Determine the symmetry of the function y=-x^3 (even, odd, or no symmetry) and explain how you arrived at your answer. Again, this wasn't in my lesson... Unless I missed it, trying to find it again...

Answer 1

So it would be no sym. Right?

Answer 2

looks like it has rotational symmetry to me

Answer 3

a function \(f(x)\) has odd symmetry iff \[f(-x)=-f(x)\]
even symmetry iff \[f(-x)=f(x)\]

Answer 4

\[y=f(x)=-x^3\]

\[f(-x)=-(-x)^3=\]