Part 1: Solve each of the quadratic equations below. Show your work.

x2 − 25 = 0 and x2 = 2x + 15

Part 2: Describe what the solution(s) represent to the graph of each.

Part 3: How are the graphs alike? How are they different?

Question

Part 1: Solve each of the quadratic equations below. Show your work. 

x2 − 25 = 0 and x2 = 2x + 15

Part 2: Describe what the solution(s) represent to the graph of each.

Part 3: How are the graphs alike? How are they different?

anonymous · Answer

x^2 - 25 => x^2 - 5^2 therefore it = (x-5)(x+5) so, $$x=\pm5$$
x^2-2x-15=0 => (x-5)(x+3), so, x = 5 and x=-3.

each solution to each graph represents the x- intercepts

alike: both have an x-intercept of +5, both are quadratic.
different: the ratio of y values to x values are different excluding x=5

migitmack · Answer

did that say x=+5?, it looks a  bit weird