Question

What is the distance, CD, between the boats?

Answer 1

@apoorvk @jim_thompson5910

Answer 2

Hint:

SOH-CAH-TOA:
SOH : \(sin \theta = \huge \frac{opposite}{hypotenuse} \)

CAH : \(cos \theta = \huge \frac{adjacent}{hypotenuse} \)

TOA : \(tan \theta = \huge \frac{opposite}{adjacent} \)

Answer 3

is it 173.2?

Answer 4

Hint 2:
BD - BC = CD

Answer 5

Hint 3:
AB = opposite side = 200 ft

Answer 6

is it 173.2 ?? thats what im getting. im asking if its correct

Answer 7

@dpaInc

Answer 8

173.2 is incorrect

Answer 9

ok thanks! 284.3 is this it @jim_thompson5910 :)

Answer 10

\[\sin \theta = \large \frac{opposite}{hypotenuse} = \frac{200 ft}{H ft} = \sin 30^o\]

Answer 11

One way of going about it :-) (there's more than one correct method)

Answer 12

Why use sine when you want the adjacent sides (and you're given the opposite side)? I'd go with tangent.

Answer 13

*shrug* Or tangent is fine :D

Answer 14

Then again, there is more than one way to do this.

Answer 15

you're getting closer HELP001, but that's still not it

Answer 16

230.9 ft @jim_thompson5910 this has to be it!

Answer 17

you nailed it

Answer 18

I got about the same answer going another way, so double correct. :D

Answer 19

THANKS :P

Answer 20

You all can type on calculators fast than I :P