Question

Equivalent terms - Question is attached

Answer 1

2x√(3x)

Answer 2

Thanks, could you tell me why?

Answer 3

\[\sqrt{3x^2} = x \sqrt{3}\]

and \[\sqrt{3x^2} = \sqrt{3 \times x^2} = \sqrt{x^2}\times \sqrt{3} = x \sqrt{3}\]

same for the other radical

\[\sqrt{4x} = \sqrt{4 \times x} = \sqrt{4} \times \sqrt{x} = 2\]

so the problem is now

\[x \sqrt{3} \times 2\sqrt{x} = 2x \sqrt{3x}\]

Answer 4

Thanks a lot