can someone please help me with steps? what would the standard equation of the line of a parabola be if it has a vertex of (6,6) and passes through the point (6.1, 1.5)?

i tried using the points to find the equation of a straight line then integrate the straight line to get the equation of the parabola but i seem to be doing it wrong? is my approach wrong? i mean am i just over complicating things or is there no easier way?

Question

can someone please help me with steps? what would the standard equation of the line of a parabola be if it has a vertex of (6,6) and passes through the point (6.1, 1.5)? 

i tried using the points to find the equation of a straight line then integrate the straight line to get the equation of the parabola but i seem to be doing it wrong? is my approach wrong? i mean am i just over complicating things or is there no easier way?

parthkohli · Answer

Hey Michelle, please pardon me. I don't know how to do this problem. Let me give a message to you for now:

This site is very inactive as it is not working today, so please be patient while they fix it up :)

anonymous · Answer

lol  thanks... i have time so dont worry ill wait.. :)

parthkohli · Answer

Thank you for your patience!

ash2326 · Answer

Yeah Michelle. there's an easy way
Standard equation of a parabola with vertex (h, k) is given as
$$y=a(x-h)^2+k$$
where a is a constant
We are given vertex as (6, 6)
so h=6, k=6
so we get now
$$y=a(x-6)^2+6$$
Now you just need to find a, we have a point on the parabola given (6.1, 1.5)
put x=6.1 and y=1.5  in the equation
$$1.5=a(6.1-6)^2+6$$
Now from this you can find " a" and and voila !! we have the equation

anonymous · Answer

ah  ha... wow thanks thats really too simpleX_X.... thanks alot :)

ash2326 · Answer

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