Question

please help!
x+4y-z=1
3x-y+8z=0
x+4y-z=10

Answer 1

what is the value of each variable?

Answer 2

pick two equations out of the three first so lets do the first two

Answer 3

ok i did the question and i got 0=9 but i dont know what to do next!

Answer 4

how did u do the question and how did u get 0=9

Answer 5

pick x+4y-z=1 and 3x-y+8z=0

Answer 6

i did the process of elimination and got rid of the x variable then after doing that on two of the equations i got 0=9 on both but i dont know what to do next!

Answer 7

multiply 4 to 3x-y+8z=0

Answer 8

lets cancel the y's first

Answer 9

ok

Answer 10

so did u multiply the 4?

Answer 11

yup! i got 12x-4y+32z=4

Answer 12

actually the 4 at the end is a 0 because 4*0=0

Answer 13

oh whoops...

Answer 14

12x-4y+32z=0

Answer 15

yes then add or subtract the two equations now so
x+4y -z =1
+12x-4y+32z=0

Answer 16

so the y's cancel out and ur left with 13x+31z=1

Answer 17

yea ok

Answer 18

do you now do the same ot the other equation? cancel the ys

Answer 19

yes u do, but actually this problem doesn't have an answer

Answer 20

it doesnt? so its like a no solution vertical line?

Answer 21

yes it is

Answer 22

sorry, i should have figured that out earlier, i made u go through all this mess and wasted ur time......

Answer 23

no its ok :)

Answer 24

well u got it now :)

Answer 25

thanks!!

Answer 26

ur welcome :)