Question

The equation of a circle is (x + 6)2 + (y + 2)2 = 16. The point (-6, 2) is on the circle.

What is the equation of the line that is tangent to the circle at (-6, 2)?
A.y= -2
B.x= -2
C.x= 2
D.y= 2

Answer 1

those should be (x+6)^2 right?

Answer 2

yep

Answer 3

this for calc?

Answer 4

yeah

Answer 5

that point cant be on the circle, it is the center

Answer 6

o wait nm

Answer 7

well we dont need calc, because the like tanget to the point will be orthogonal to the line from the radius to the point

Answer 8

do you have to use calc?

Answer 9

D.y= 2

Answer 10

yah you will have to implicit to differentiate

Answer 11

no need for that, :). Just imagine the picture