For a quadratic function, f(1)=5, f(2)=-7, f(3)=-11 find f(-2) I'm studying for my exam and do not know how to do this. Please help me and tell me step by step. Thank you!
do you know the general form for a quadratic equation?
isn't it ax^2+bx+c
thats right. so you know your function is of the form:\[f(x)=ax^2+bx+c\]
a, b and c are three unknowns here
and you have been given three values for f(x)
you should be able to use these values to find a, b and c
so what i did was a+b+c=5 4a+2b+c=-7 9a+3b+c=-11 but Im not sure what to do next to find f(-2)
use the 3 equations to solve for a, b and c. then use these values of a, b and c to find f(-2)
does that make sense?
would a matrices help?
you could use matrices, but these equations are fairly simple. e.g.: a+b+c=5 (1) 4a+2b+c=-7 (2) 9a+3b+c=-11 (3) 3a+b=-12 (2) - (1) 5a+b=-4 (3) - (2)
then eliminate b from the 2 new equations and solve for a then find b then find c
so i got f(-2)=-535…but i don't think that is right
i got a=4, b=-24, c=25
those are correct
so you now have:\[f(x)=4x^2-24x+25\]
how did you calculate f(-2)?
so i now got 89 i think i did something wrong on my calculator
yup - that's the correct answer - well done! :)
Thank you so much for your help!!
yw :)
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