Question

GCF of 12ab^2c^4+72a^2b^3c^5

Answer 1

\[12ab^2c^4+72a^2b^3c^5\]
each term has a 12 since \(72=12\times 6\)
each term has an \(a\) also a \(b^2\) and also a \(c^4\) so it is
\[12ab^2c^4\] the first term

Answer 2

if you multiply it by \(6abc\) you get the second term

Answer 3

Would the answer be 12ab^2c^4 (6abc) ?

Answer 4

12a*b^2*c^4(1+6abc)

Answer 5

could i write as a+6abc . is that the same thing ?

Answer 6

It will be 12b^2*c^4(a+6a^2*b*c)

Answer 7

Thats what im saying .

Answer 8

Right.