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Find the distance between the points: (2,0) and (3,-3)
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use the distance formula: \(\large Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \)
did you try it yet?
totally lost brother
oh is it 10
ok... subtract the x-coordinates... then square that answer... what u got?
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what is the particular solution of ydx + (2x +3y)dy=o when the answer is xy^2 + y^3
dpalnc i got 10
is that your answer to my last question or is 10 the distance?
10 is the distance
that is homogeneous differential equation
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i think 10 is just the ths part right? : \(\large (x_2-x_1)^2+(y_2-y_1)^2 \)
yes
so put a square root over that 10 and that's your answer...
3.16
about 3.16..... but exactly \(\large \sqrt{10} \)
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