Question

3 = log8 + 3logx.
Solve for x.

Answer 1

i dont no what it is

Answer 2

Me either

Answer 3

\(\large 3=log8+3logx \)
\(\large 3=log8+log(x^3) \)
\(\large 3=log(8\cdot x^3) \)

now write that last line in exponential form... can you do that?

Answer 4

Would it be 8^x3=3?

Answer 5

no... that problem is the common log right? base 10?

Answer 6

Yes it is

Answer 7

so where's the 10 in your equation?

Answer 8

It's not shown. I thought there would be one but that's all it had :/

Answer 9

\[\huge log_bM=x \Rightarrow b^x=M \]

Answer 10

your base is 10, and your exponent is the 3. the M is whatever is in the parenthesis...

Answer 11

Okay

Answer 12

I think I got how to do it

Answer 13

so your equation in exponential form should be: \(\large 10^3=8x^3 \)

Answer 14

ok.... good luck to you...