Question

Simplify : (3x^4)^3
a. 27x^7
b. 3x^7
c. 3x^12
d. 27x^12

Answer 1

Hint: \(\large(x^{a})^{b} = x^{ab}\)

Answer 2

So:
\[\large(3x^{4})^{3} = 3^{3}x^{4(3)}\]

Answer 3

\[(xy)^n=x^ny^n\]

Answer 4

@golikrishna There's something wrong with your answer. The ^12 would not be distributed to the 3 as well, but rather the original 3 would be distributed to the 3.

Answer 5

yes

Answer 6

27x^12