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if f(x)=6x-4 g(x)=x-2 how do i find (f of g)(x)
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(f of g)(x)=f(g(x))=f(x-2) now just put x-2 instead of x in f's equation
what will u get?
6x(x-2)-4?? is that my equation
almost /
\[f(x)=6(x)-4\] \[f(a+b)=6(a+b)-4\]
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6(x-2)-4??
yeah! now you can simplify a little bit and your done
6x-8
not quite
after 6(x-2)-4 should i get 6x-12-4..
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6x=16?
\[f\circ g(x)=6x-16\] is right
yay okay thanksss
im going to close this question, and im going to ask another one..*hince* i want you to help me again :) if you can ha
ill see what i can do
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