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what is the equation of the line whose slope is 0 and that contains the point (-4, 2).
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0 slope means horizontal line
\(y=mx+b\) \(m=0\) => \(x=-4,y=2\) Sub it in to find \(b\) After finding the variable \(b\) you will find the equation.
okay you said a horizontal line?
horizontal line yes
so its either y+4=0 or y-2+0? at igbasallote?
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you don't need to worry about horzontal line i suppose.
\(2 = 0(-4)+b\) => \( 2 = 0+b\) => \(b=2\) \(y= 0(x) +2\) => \(y=2\)
so y-2=0?
well.. \(y-2=0\) => \(y=2\) same equation.
okay thanks!
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np
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