Question

Given the triangle below, what is sec∡C?

Answer 1

Option A

Answer 2

Option B

Answer 3

Option C

Answer 4

Option D

Answer 5

SOH-CAH-TOA:
SOH : \(\sin \theta = \large \frac{opposite}{hypotenuse} \)

CAH : \(\cos \theta = \large \frac{adjacent}{hypotenuse} \)

TOA : \(\tan \theta = \large \frac{opposite}{adjacent} \)

Use \(a^2+b^2=c^2\) to find missing sides

Secant is the inverse of cosine, \(\large\frac{1}{\cos\theta}\)

Answer 6

Can you name the sides adjacent to C and the hypotenuse that touches C?

Answer 7

I would use cos

Answer 8

Inverse.

Answer 9

You don't have to find the missing side.
cos C = AC/BC
sec C = 1/cosC = 1/ (AC/BC) = BC / AC =...

Answer 10

\(\large\frac{hyp}{adj}\)

Answer 11

So how would i work it out?

Answer 12

What's your hypotenuse?

Answer 13

7

Answer 14

;-)

Answer 15

Yep, and the other side adjacent to \(\angle C\)?

Answer 16

4

Answer 17

So, what did I say earlier?

Answer 18

hypotenuse/adjacent
7/4=1.75

Answer 19

;-)

Answer 20

ok, got it. Thank you both :)