5/6 - (-7/12)
\[\huge{\frac{5}{6}-\frac{-7}{12}}\] Take LCM : here it is 12 \[\huge{\frac{(5*2)-(-7*1)}{12}}\] \[\huge{\frac{10-(-7)}{12}}\] Can u solve this further ?
ummm soory i really bad at this and this is my last question please ....
please help me
(5/6)-(-7/12) we have two ratios. what you want to do so that you can add them, is make it so they have the same denominator. we think about what number both of these numbers devide and see that such a number is 12. ok so lets deal with the ratio on the left, what do we need to do to the denominator to make it a 12? multiply it by 2, ratios have the property that if you multiply the top and bottom by the same number then you still have the same ratio. so we needed to multiply the bottom by 2 so we must do the same for the top. ((5(2))/(6(2)))=10/12 = 5/6(so we we wrote 5/6 as 10/12) now we have (10/12) - (-7/12) a negative can be distributed such that we get a negative * negative thus a positive so (10/12)+(7/12) now we just retricethe top and keep the bottom 10+7 = 17 so 17/12
so 17/ 12 is the answer ?
now we just add the top and keep the bottom*
you tell me:) we ar ehere to make sure you understand not just to get the answer
if you just want the answer type it into google
No i know that , and i really thank you for this help
but yes that is the answer, you can always just plug these things into a site like wolframalpha.com to get the answer and check.
i got 1.41666666666666666666666666666666
is that the same thing as 17/12?
no
idk i think not
type 17/12 into google
you should give you answer in fraction form not decemel so maybe wolframalpha.com would be a better place to check such things
thank you bud ur a saver thank you man and have a good night .
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