Question

(30x^3y^-5 over 150x^-4y^2)^2

raise the quantity in the parentheses to indicated exponent, then simplify--use positive exponents

Answer 1

cud u write it as an equation. its not clear

Answer 2

((30x^3y^-5)/(150x^-4y^2))^2

Answer 3

Hey, Alice! Welcome to Openstudy! Is this the problem?

\( \color{Black}{\Rightarrow \Large \left ({30x^3y^{-5} \over 150x^{-4}y^{2}} \right )^2 }\)

Answer 4

ohh okk

Answer 5

yes

Answer 6

Okay. So you have to compute these first:

\( \color{Black}{\Rightarrow \Large {30 \over 150}}\)

\( \color{Black}{\Rightarrow \Large {x^3 \over x^{-4}}}\)

\( \color{Black}{\Rightarrow \Large {y^{-5} \over y^2}}\)

Answer 7

x^a / x^b = x ^ (a-b)

Answer 8

Do you know the properties of exponents? The ones you gotta use here are:

\( \color{Black}{\Rightarrow x^a \div x^b = x^{a - b} }\)

\( \color{Black}{\Rightarrow (x^a)^b = x^{a\times b} }\)

Answer 9

For example:

\( \color{Black}{\Rightarrow \Large {x^3 \over x^{-4} }\normalsize = x^{3 - (-4)} = x^7 }\)

Answer 10

Did you get it? @Ladyalice25

Answer 11

so the equation so far will look like x^7/5y^7 is that correct

Answer 12

No!

Answer 13

\( \color{Black}{\Rightarrow \Large {30 \over 150} = {3 \over 15} = {1 \over 5} = \normalsize 0.2}\)

\( \color{Black}{\Rightarrow \Large x^3 \div x^{-4} = x^7}\)

\( \color{Black}{\Rightarrow \Large {y^{-5} \div y^2} = y^{-5 - 2}=y^{-7}}\)

Answer 14

Combine 'em all

\( \color{Black}{\Rightarrow\left ( 0.2x^7y^{-7} \right) ^2 }\)

Answer 15

The final answer will then look like

\( \color{Black}{\Rightarrow 0.2^2 \times x^{7 \times 2} \times y^{-7 \times 2} }\)

\( \color{Black}{\Rightarrow 0.04 \times x^{14} \times y^{-14} }\)

Answer 16

k thank you know i understand it

Answer 17

You're welcome!