Question

A number is chosen from a list 2,4,6 and 8. Another is selected from from the list 6,7 and 8. Find the probability that they are the same.

Answer 1

req probability = (2/4) * (2/3)

Answer 2

as 2 nos are a part if favorable outcomes from both lists..

Answer 3

I don't really get what you just said lol

Answer 4

good because i am pretty sure it is not right

Answer 5

Good.

Answer 6

from 1st list, there are 4 nos : 2,4,6,8
in 2nd : 6,7,8
2 nos i.e. 6 and 8 are common to both
we select a no. each from the list..
probability of selecting 6 or 8 from 1st list = 2/4
from 2nd list = 2/3
we want both to happen simultaneously, so req probab = 2/4 * 2/3

Answer 7

ohh..please correct me.

Answer 8

picture of problem

Answer 9

there are two outcomes favorable
both are 6 or both are 8
the probability both are 6 is
\[\frac{1}{4}\times \frac{1}{3}=\frac{1}{12}\] the probability both are 8 is the same,\(\frac{1}{12}\)
you want one of the other, and since these events (both 6 or both 8) are mutually exclusive, you can add the probabilities together

Answer 10

so you just add them together?

Answer 11

yes just add

Answer 12

because the events are "disjoint" simply meaning you cannot get two 6 and at the same time two 8
in such a case an "or" statement i.e. one or the other you compute by adding

Answer 13

ohh yes yes,,i see what i did..i even included (6,8) and (8,6) in my ans
sorry
and thank you @satellite73
hmmm

Answer 14

you can think of it this way
there are 12 outcomes all together which just 2 of them are favorable so
the answer is 2/12 = 1/6

Answer 15

yep..get it now @Kasra
sorry again.. :|

Answer 16

thanks!