Question

Choose the equation of the line passing through the point (-2, 6) and parallel to y = 1/2x-8

Answer 1

y=1/2x-8, P(-2,6)

solving for dy/dx
y=1/2x-8
substitute -2 to x
y=1/2(-2)-8
y=(1/-4)-8
y=-33/4

since
dy/dx=m m=slope
m=-33/4

using point slope form equation of the line
y_2-y_1=m(x_2-x_1)

let x_2 =x x_1=-2
y_2=y y_1=6

y-6=-33/4(x+2)
y-6=(-33/4x)+(-33/2)
(-33/4x)+(y)-(6)-(-33/4)=0
(-33/4x)+y-(57/4)=0 <<<<<<<equation of ur tangent line or parallel line