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Mathematics 19 Online
OpenStudy (anonymous):

In a certain county, the number of Charter Schools is six less than twice the number of Alternative Schools. We know that there are 52 Charter Schools in the county. How many Alternative Schools are in the county?

OpenStudy (mathteacher1729):

So this is a classic example of "translating words into math". Here's the evolution of it... The number of Charter Schools is six less than twice the number of Alternative Schools. The number of Charter Schools = six less than twice the number of Alternative Schools. The number of C = six less than twice the number of Alternative Schools. The number of C = six less than twice the number of A. The number of C = six less than 2A. The number of C = 2A - 6. C = 2A - 6.

OpenStudy (anonymous):

This can be expressed as an equation where Charter Schools are X and Alternative Schools are Y. Putting this in an equation: \[x=2y-6\] Now if you plug in the value of x: \[52=2y-6\] Now isolate the y by adding 6 to both sides: \[58=2y\] Now divide by two to get the value of y \[y=29\]

OpenStudy (anonymous):

i cant give two medals bu thank both of you

OpenStudy (anonymous):

No problem :)

OpenStudy (mathteacher1729):

Basically this: We know that there are 52 Charter Schools in the county. Means this: C = 52

OpenStudy (mathteacher1729):

So now you have to solve C = 2A - 6. with C = 56 But that's just 56 = C = 2A - 6 So "take out the middle man" (the C) and 56 = 2A - 6 And now solve for A. :)

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