Help! How do I solve this linear equation? 6x-y+z=0 4x+2y-3z=18 x-3y+2z=-15
can you use matrices?
i can. im teaching myself.
\[\left(\begin{array}\\6&-1&1\\4&2&-3\\1&-3&2\end{array}\right)\left(\begin{array}\\x\\y\\z\end{array}\right)=\left(\begin{array}\\0\\18\\-15\end{array}\right)\]
right...now what do i do?
do you know the valid row operations you can apply?
you can multiply any row by a constant \[R_n\rightarrow \alpha R_n\]simply multiply each of the 5 terms in the top row by a scalar
You are really confusing me
you can swap an entire row with another \[R_n\longleftrightarrow R_m\]
maybe matrices isn't a good idea then
the other operation you can do is add or subtract one row from another\[R_n\rightarrow R_n\pm R_m\]
I know matrices and I know for a fact that @UnkleRhaukus is confusing you
You can't teach someone something for the first time that way
what is the easy way to solve this
I'm saying, you can use matrices, but your approach to demonstrating it will most likely confuse
I'm going to avoid saying "teach" here
add all the equations together what do you get (6x-y+z)+(4x+2y-3z)+(x-3y+2z)=0+18-15
\[(6x+4x+x)+(-y+2y-3y)+(z-3z+2z)=3\]
ok that dosent work either, i still cant see an simply way to do this
Drawing button ?
ive figured it out
did you get x=1
How?
i added
x=1 y=4 and z=-2
You can't just "add".
thats right, i want to know your steps helpmewithmath2012
You have to perform a sequence of operations
I don't think she/he will show them
just outline the method i want to know which rows to add
i want to know your method too hero
i solved y by getting 11x+2y=3 y=4 but idk how i got x and z
did you do it in you head or use paper @helpmewithmath2012 ?
my head so now im trying to figure out what i did
do you know how to find the determinant of a matrix?
Can't you simply use row reduction until you get something like|dw:1341437005879:dw|? @UnkleRhaukus
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