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f(x)=sin2x g(x)=x^2-7 find g(f(x))
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To find g(f(x)) put sin2x in place of x in g(x).. Getting??
and what would that become?
You show me then I will tell you whether it is right or wrong..
(sin2x)^2-7
Yes now take the square of sin2x..
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you mean (sin2x)(sin2x)
No.. x*x = x^2
\[\huge (\sin2x)^2 = \sin^22x\]
Getting??
erm not that no.
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Are you provided with choices or not?
\[\huge (\sin2x)^2 = \sin^22x\] These are one and the same thing..
so how do you get from one to the other?
See in case of trigonometry: \[\sin^2x\]\[\huge \sin^2x \implies (sinx)^2\]
are you provided with the choices??
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you are right if that is what you mean.
Yeah I mean it..
but I do understand how sin^2 x is the same as (sin2x)^2
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