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write the standard form of the equation of the parabola whose directrix is x=-1 and whose focus is at (5,-2)
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\[ (x+1)^2 = (x-5)^2 + (x+2)^2 \]
hmm not one of my choices
\[ (x+1)^2 = (x-5)^2 + (y+2)^2 \]
a) (y+2)^2=12(x+2) b) y-2=12(x+2)^2 c) x+2=1/12(y+2)^2 d) x-2=1/12(y+2)^3
*****d)x-2=1/12(y+2)^2
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It is d. You can simplify my answer above to get that.
ok thanks
\[ (x+1)^2-(x-5)^2=(y+2)^2\\ 12 x-24=(y+2)^2\\ 12( x-2)=(y+2)^2\\ ( x-2)=\frac 1 {12}(y+2)^2 \]
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