Question

Write the equation of the line that passes through (2, 2) and (6, 3) in standard form?

I ended up with fractions... anyone mind walking me through it ?

Answer 1

slope = 3-2 / 6-2) = 1/4
use the standard form

y - y1 = m(x - x1) m=slope and (x1,y1) is a point on the line
so use the point (2,2):
y - 2 = (1/4)(x - 2)
now multiply the equation by 4 to get rid of fraction:
4y - 8 = x - 2
x - 4y = -6 - standard form

Answer 2

thank you! But how did you get your ending result answer from 4y - 8 = x - 2?

Answer 3

ok? -need further help?

Answer 4

ok - i did some steps in my head
4y - 8 = x - 2
add 8 to both sides
4y = x + 6
subtract 4y form both sides
0 = x - 4y + 6
now subtract 6 from both sides
-6 = x - 4y
then flip the values over the = to give
x - 4y = -6

as i understand it standard form is like ax + by = c

Answer 5

now i see;) thank you!