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Mathematics 51 Online
OpenStudy (anonymous):

Mia plans to cover a portion, ADC, of a collage with two triangular pieces of cardboard. She cuts out the first piece of cardboard BCD, as shown below. What is the length of side AB of the second piece of cardboard, ABD, which Mia has to cut? 23.1 cm 34.6 cm 11.5 cm 19.3 cm

OpenStudy (anonymous):

OpenStudy (anonymous):

you know how to use sohcahtoa?

OpenStudy (anonymous):

umm i think so.. sin = opposite/hypotenuse cos= adjacent/hypotenuse and tan= opposite/adjacent i know how to use them but it only gives one side length

OpenStudy (anonymous):

if you do use it to find BC and AC then get AB

OpenStudy (anonymous):

yea that's right. in this case you are given adjacent side = 20, you only need to find the opposite side

OpenStudy (anonymous):

but i only have 1 side length.. thats what i dont understand how can i solve for it with only one side length

OpenStudy (anonymous):

so the adjacent side will be one of the answer choices? then what?

OpenStudy (anonymous):

for BC tan 30 = BC/DC for AC tan 60 = AC/DC

OpenStudy (anonymous):

so it would be 34.6?

OpenStudy (anonymous):

??

OpenStudy (anonymous):

woops sorry went afk. i got 23.1

OpenStudy (anonymous):

its okay. umm can you explain it step by step how you did it?

OpenStudy (anonymous):

tan 30 = BC/20 BC = 20 tan 30 = 11.6 tan 60 = AC/20 AC = 20 tan 60 = 34.6 AC - BC = 23

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