Mathematics
11 Online
OpenStudy (anonymous):
lne^-5
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OpenStudy (anonymous):
\[\ln a=b \\ then \\ e^b=a\]
am i right?
OpenStudy (anonymous):
confused a little...
OpenStudy (anonymous):
ln equals log base e
\[\log_{e} a=b \\ \\ equals \\ \ln a=b\]
OpenStudy (anonymous):
do u know the properties of log?
OpenStudy (anonymous):
honestly i dont know..
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OpenStudy (anonymous):
well...
@satellite73
OpenStudy (anonymous):
hahahaha why did you call him???
OpenStudy (anonymous):
@Mimi_x3
OpenStudy (mimi_x3):
well, what do you need help with since you tagged me?
OpenStudy (anonymous):
MY QUESTION...
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OpenStudy (mimi_x3):
What do you want to do with \(lne^{-5}\)?
OpenStudy (anonymous):
simplify
OpenStudy (anonymous):
please
OpenStudy (anonymous):
dont give me the answer.. help me work it out if you can
OpenStudy (mimi_x3):
\(lne^{-5}\) => \(-5ln(e)\)
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OpenStudy (mimi_x3):
I am not sure if this is a correct way of doing it..haven't touched logs in a while..
OpenStudy (anonymous):
hha okay! well thank you.. is there a formula you used?
OpenStudy (mimi_x3):
There is I suppose; but I cannot remember it.
OpenStudy (mimi_x3):
@lgbasallote: might know!
OpenStudy (anonymous):
okayyy! thanks so muchh
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OpenStudy (lgbasallote):
@Mimi_x3 @clcboo123 what's the problem?
OpenStudy (mimi_x3):
What is the formula for.. \(lne^{-5} => -5lne\)
?
OpenStudy (anonymous):
@lgbasallote
OpenStudy (anonymous):
mimi typed the question for you....
OpenStudy (lgbasallote):
\[\ln e^{-5} = -5\]
according to
\[\ln e^a = a\]
this is a logarithmic property
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OpenStudy (mimi_x3):
Wait I got it lol
\(logA^{n} = n*logA\)
OpenStudy (lgbasallote):
but if you want long way...
\[\large \ln e^{-5} \implies -5 \ln e \implies -5 (1) \implies -5\]
OpenStudy (anonymous):
thank you both!!!! :)
OpenStudy (mimi_x3):
the same way i mentioned lol; she did not want the answer (:
OpenStudy (mimi_x3):
You're Welcome!
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OpenStudy (lgbasallote):
lol it's an automatic property
OpenStudy (lgbasallote):
i wasnt giving the answer haha