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Mathematics 11 Online
OpenStudy (anonymous):

lne^-5

OpenStudy (anonymous):

\[\ln a=b \\ then \\ e^b=a\] am i right?

OpenStudy (anonymous):

confused a little...

OpenStudy (anonymous):

ln equals log base e \[\log_{e} a=b \\ \\ equals \\ \ln a=b\]

OpenStudy (anonymous):

do u know the properties of log?

OpenStudy (anonymous):

honestly i dont know..

OpenStudy (anonymous):

well... @satellite73

OpenStudy (anonymous):

hahahaha why did you call him???

OpenStudy (anonymous):

@Mimi_x3

OpenStudy (mimi_x3):

well, what do you need help with since you tagged me?

OpenStudy (anonymous):

MY QUESTION...

OpenStudy (mimi_x3):

What do you want to do with \(lne^{-5}\)?

OpenStudy (anonymous):

simplify

OpenStudy (anonymous):

please

OpenStudy (anonymous):

dont give me the answer.. help me work it out if you can

OpenStudy (mimi_x3):

\(lne^{-5}\) => \(-5ln(e)\)

OpenStudy (mimi_x3):

I am not sure if this is a correct way of doing it..haven't touched logs in a while..

OpenStudy (anonymous):

hha okay! well thank you.. is there a formula you used?

OpenStudy (mimi_x3):

There is I suppose; but I cannot remember it.

OpenStudy (mimi_x3):

@lgbasallote: might know!

OpenStudy (anonymous):

okayyy! thanks so muchh

OpenStudy (lgbasallote):

@Mimi_x3 @clcboo123 what's the problem?

OpenStudy (mimi_x3):

What is the formula for.. \(lne^{-5} => -5lne\) ?

OpenStudy (anonymous):

@lgbasallote

OpenStudy (anonymous):

mimi typed the question for you....

OpenStudy (lgbasallote):

\[\ln e^{-5} = -5\] according to \[\ln e^a = a\] this is a logarithmic property

OpenStudy (mimi_x3):

Wait I got it lol \(logA^{n} = n*logA\)

OpenStudy (lgbasallote):

but if you want long way... \[\large \ln e^{-5} \implies -5 \ln e \implies -5 (1) \implies -5\]

OpenStudy (anonymous):

thank you both!!!! :)

OpenStudy (mimi_x3):

the same way i mentioned lol; she did not want the answer (:

OpenStudy (mimi_x3):

You're Welcome!

OpenStudy (lgbasallote):

lol it's an automatic property

OpenStudy (lgbasallote):

i wasnt giving the answer haha

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