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solve the equation f(x)=g(x) algebraically. f(x)= ln(x-4) g9x)=0
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so you need to solve: \[\huge 0=ln(x-4) \]
can you write this in exponential form?
how do you do that? :O
any exponential equation can be written in logarithmic form and vice versa... \[\huge b^M=N\Leftrightarrow log_bN=M \]
so in your case.. \[\huge ln(x-4)=0\Leftrightarrow e^0=x-4 \]
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do you know what \(\large e^0= \)????
1? sorry late reply
ooops... I mean \[1=x-4\]
\[e^0 = 1\] therefore \[1 = x - 4\] now solve for x
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