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Mathematics 21 Online
OpenStudy (anonymous):

What is the equation of the following graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (zepp):

Where is your graph centered at?

OpenStudy (anonymous):

-5,3?

OpenStudy (zepp):

Almost, you just reversed x-axis' value with y-axis' :)

OpenStudy (zepp):

Coordinates are always patterned like this: \((x,y)\)

OpenStudy (anonymous):

3,5?

OpenStudy (zepp):

\((3,-5)\) You lost the negative sign

OpenStudy (anonymous):

would it b B?

OpenStudy (zepp):

Okay, this is a hyperbola, and it's standard form is \[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\] Replace values.\[\large \frac{(x-(3))^2}{2^2}-\frac{(y-(-5))^2}{2^2}=1\] \[\large \frac{(x-3)^2}{2^2}-\frac{(y+5)^2}{2^2}=1\] Should be A)

OpenStudy (anonymous):

thank you so much! :)

OpenStudy (zepp):

You are welcome :)

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