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Mathematics 13 Online
OpenStudy (lgbasallote):

there are 40 students in a class. 3 students are to be chosen as representatives. which is used here? permutation or combination?

mathslover (mathslover):

i think combination .. combination is used for selection

OpenStudy (lgbasallote):

so the answer would be \[\frac{40!}{3!37!}?\]

mathslover (mathslover):

Yes ! i think so

OpenStudy (lgbasallote):

so when do you use permutation?

OpenStudy (anonymous):

combination , order doesn't matter.

OpenStudy (lgbasallote):

so when to use permutation?

mathslover (mathslover):

ppermutation is used with several slightly different meanings, all related to the act of permuting (rearranging) objects or values

mathslover (mathslover):

combination is a way of selecting several things out of a larger group, where (unlike permutations) order does not matter.

Parth (parthkohli):

When you gotta choose people from a committee ---> COMBINATIONS When you gotta find the number of ways to arrange(in different orders) ---> PERMUTATIONS

OpenStudy (alexwee123):

Well if the 3 positions were like special like they have specific roles it would be permutations i think :/

Parth (parthkohli):

NO! Combinations

Parth (parthkohli):

Number of ways to choose 3 people ---> 40 choose 3 ---> 40C3

OpenStudy (apoorvk):

Ze answer's in ze question! "to be chosen" ----> choose -----> Combinations If it had been some thing like "to be chosen and a queue be formed" and then the no. of ways to do this, then Mr. Permutation would have come into play.

OpenStudy (lgbasallote):

ohhhhh...but i've seen some problems wherein there's no order specified but permutation was used...is that possible?

OpenStudy (apoorvk):

Can you post some examples of those questions?

OpenStudy (lgbasallote):

it was long ago..i just saw a problem here that was answered that way...maybe it was just a wrong solution?

OpenStudy (anonymous):

Permutation: It is used when we have to select something and to arrange it too.. Combination: It is used when we have to select only..

Parth (parthkohli):

Wanna know the difference? 40C3 is the number of ways you could take out 3 people from 40 people. 40P3 is the number of ways you could take out 3 people from 40 people, AND ARRANGE THE 3 PEOPLE IN DIFFERENT ORDERS.

OpenStudy (lgbasallote):

so let's say a committee..is that permutation or combination? it's combination right? because the members of a committee doesnt need to be arranged?

Parth (parthkohli):

Yeah! :)

OpenStudy (lgbasallote):

can you give an example of a permutation problem? i cant visualize it.. the one with the select and arrange thingy

Parth (parthkohli):

The number of ways you could arrange 50 different markers in a packet is supposed to be 50P50.

Parth (parthkohli):

The number of ways you could arrange 50 markers in a packet that can contain only 30 markers is 50P30.

OpenStudy (lgbasallote):

but that's just arrange...i asked for *select* and arrange lol

Parth (parthkohli):

Yep, see my second example. ;)

OpenStudy (lgbasallote):

ohhhh

OpenStudy (lgbasallote):

tthe combination couter part would be the number of ways you can put 50 markers in a packet that contains 30?

Parth (parthkohli):

Yep.

OpenStudy (lgbasallote):

great thanks :D

Parth (parthkohli):

You're welcome! :)

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