solve: (x/4)=(x-2/3) A)4 B)8 C)2
\[\frac{x}{4} = x - \frac{2}{3}?\]
\[\frac{x}{4} = x - \frac{2}{3}\] \[\frac{x}{4} - x = -\frac{2}{3}\] \[\frac{x}{4} - \frac{4x}{4} = -\frac{2}{3}\] \[\frac{x-4x}{4} = -\frac{2}{3}\] \[x - 4x = -\frac{2 \times 4}{3}\] \[-3x = -\frac{2 \times 4}{3}\] can you solve for x now?
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\[\frac{x}{4} = \frac{x-2}{3}\] cross multiply \[3x = 4(x-2)\] distribute \[3x = 4x - 8\] can you solve for x now?
do you get it @nique504 ?
yes. now all i do is add 8 to each side,then divide that answer by 4 right?
no...first put all the x on one side
how can you bring 4x and 3x into one side?
i can add 4x to both sides?
then that will give you 7x = 8x - 8
right?
yes
so what happens now?
i'm not sure.
remember you want to put the x on one side only so what do you do?
subtract 4x from each side?
if you subtract 4x from both sides you get 3x - 4x = 4x - 4x - 8 3x - 4x = -8 very good the x are now on one side now what is 3x-4x?
then my answer would be 8
yup x = 8 would be right
okay, thanks for helping:)
<tips hat>
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