Let n be a natural number, and M = 5^n. If E = 3^M and E + 1 is divided by 7, then the remainder is

A. 5, when n is 212 and 4, when n is 225.
B. 4, when n is 222 and 6, when n is 225.
C. 6, when n is 222 and 5, when n is 215.
D. 6, when n is 212 and 4, when n is 215.

Question

Let n be a natural number, and M = 5^n. If E = 3^M and E + 1 is divided by 7, then the remainder is



	A. 5, when n is 212 and 4, when n is 225.
	B. 4, when n is 222 and 6, when n is 225.
	C. 6, when n is 222 and 5, when n is 215.
	D. 6, when n is 212 and 4, when n is 215.

anonymous · Answer

Rewrite E:
$$E = 3^{M} = 3^{5^{n}} = ?$$
You can simplify E down to a number to the power of n.