Question

he graph of the function g(x)=2/3(x-3)^2(x+5)^4 has a zero of multiplicity 4 at x = -5 .
True or False?

Answer 1

do you know how to find zeros?

Answer 2

Is this what you are asking:
\[g(x) = \frac{2}{3} (x-3)^2 + (x+5)^4\]
has a zero of multiplicity 4 at x = -5?

Answer 3

Or the product?
\[g(x)=\frac{2}{3}(x−3)^{2}(x+5)^{4}\]

Answer 4

I think the answer is true if the second one. because (x+5) = 0 and it is taken to the fourth power.