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\[\sum_{n=2}^{8} -(n-5)\]
i got 0 but my teacher said it was wrong
Firstly you can take -1 out of the summation sign..
Now put the values from 0 to 8..
Sorry 2 to 8..
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okay so dont make the values negative?
No it will easy to you to solve..
it would still be 0
\[-[(2 - 5) + (3-5)+(4-5)+(5-5)+(6-5)+(7-5)+(8-5)]\] \[-[-3 -2 -1 + 0 + 1 + 2 + 3]\] Yes the answer will be 0 I think..
i said the answer was 0 and my teacher was like use sigma notation so does she mean to just write it in sigma for like the value of the equation is 0
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