Question

Find the derivative:

\[y = \sqrt{x+ \sqrt{x+ \sqrt x}}\]

Answer 1

chain rule all day baby

Answer 2

i was thinking square it first...

Answer 3

nty

Answer 4

nty?

Answer 5

No thank you iggy :D.

Answer 6

oh lol

Answer 7

\[ \large \frac{1}{2\sqrt{x+\sqrt{x+\sqrt{x}}}}
\left[1+\frac{1}{2\sqrt{x+\sqrt{x}}}
\left(1+\frac{1}{2\sqrt{x}}\right)\right] \]

Answer 8

wow lol

Answer 9

that is sougly why would yu ever do that LOL!

It's deff a load of chain rules... Btw MADA MADA DANE!!!

Answer 10

you mean it's chain rule all the way o.O

Answer 11

derivative of sqrt(x) is
1/2sqrt(x)

Answer 12

lol @SmoothMath :P

Answer 13

it's basically like helder said except stacked ontop of each other like a pyramid :D.

Answer 14

or a lasagna...

Answer 15

is @helder_edwin answer right guys?

Answer 16

it looks right to me...

Answer 17

Yes, it is.

Answer 18

http://www.wolframalpha.com/input/?i=derivative+of+sqrt%28x+%2Bsqrt%28x%2Bsqrt%28x%29%29%29

:)

Answer 19

ok thanks <tips hat>

Answer 20

Thanks Echizan.