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Mathematics 72 Online
OpenStudy (anonymous):

calc 3 help suppose that the position function of a particle moving along a circle in the xy plane is r = 5cos(2pi)ti+5sin(2pi)tj. what is the distance traveled by the particle during the time interval t=0 to t=1

OpenStudy (turingtest):

use the parametric arc length formula

OpenStudy (turingtest):

\[ds=\sqrt{(\frac{dx}{dt})^2+(\frac{dy}{dt})^2}dt\]\[L=\int_a^bds\]

OpenStudy (anonymous):

Correct. \[\int\limits_{0}^{1} \left| r'(t) \right|dt\]

OpenStudy (anonymous):

oh. Didnt saw the "i" and "j". use @TuringTest 's formula instead

OpenStudy (turingtest):

eh, same thing really

OpenStudy (anonymous):

but it is easier

OpenStudy (anonymous):

So I just find ds, and integrate it along 0 and 1?

OpenStudy (turingtest):

yep

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