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calc 3 help suppose that the position function of a particle moving along a circle in the xy plane is r = 5cos(2pi)ti+5sin(2pi)tj. what is the distance traveled by the particle during the time interval t=0 to t=1
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use the parametric arc length formula
\[ds=\sqrt{(\frac{dx}{dt})^2+(\frac{dy}{dt})^2}dt\]\[L=\int_a^bds\]
Correct. \[\int\limits_{0}^{1} \left| r'(t) \right|dt\]
oh. Didnt saw the "i" and "j". use @TuringTest 's formula instead
eh, same thing really
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but it is easier
So I just find ds, and integrate it along 0 and 1?
yep
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