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Mathematics 14 Online
OpenStudy (anonymous):

Choose the system of inequalities that matches the graph below. A.4x + y > 3 2x – 5y 15 B.4x + y 3 2x – 5y > 15 C.4x + y 3 2x – 5y < 15 D.4x + y > 3 2x – 5y 15

OpenStudy (anonymous):

OpenStudy (helder_edwin):

can you find the equations of the lines in the picture?

OpenStudy (anonymous):

No

OpenStudy (helder_edwin):

OK. lest work together!

OpenStudy (helder_edwin):

first the solid line. OK?

OpenStudy (helder_edwin):

the line passes through the points (0,-3) and (7.5,0) is this right?

OpenStudy (anonymous):

Yes

OpenStudy (helder_edwin):

ok can you compute the slope?

OpenStudy (anonymous):

Is it -2.5 ?

OpenStudy (anonymous):

Or is it 0.4 ?

OpenStudy (helder_edwin):

let's see \[ \Large m_1=\frac{y_0-y_1}{x_0-x_1}=\frac{-3-0}{0-7.5}=\frac{-3}{-7.5}=0.4=\frac{2}{5} \]

OpenStudy (helder_edwin):

did you do this?

OpenStudy (anonymous):

Yes thats what I did !

OpenStudy (helder_edwin):

remember (usually) it is always better to work with fractions that decimals!

OpenStudy (anonymous):

Ok , but how will I make an equation out of this ?

OpenStudy (helder_edwin):

good question! we now have the slope and two points of the line! the standard equation is \[ \Large y-y_0=m_1(x-x_0) \] can you find the equation?

OpenStudy (helder_edwin):

you can use either one of the two points you have!

OpenStudy (anonymous):

what would be the y and x ?

OpenStudy (helder_edwin):

just keep the x and y. you have to replace x_0 and y_0. for example you can use \[ \Large (x_0,y_0)=(0,-3) \] or \[ \Large (x_0,y_0)=(7.5,0) \]

OpenStudy (anonymous):

y+3=.4(x-0)

OpenStudy (helder_edwin):

yes! \[ \Large y+3=0.4x \]

OpenStudy (helder_edwin):

can you do the same job for the dashed line? the line passes through (0,3) and (0.75,0) (i'm not sure about this one) , right?

OpenStudy (anonymous):

y-7.5=.4(x-0)

OpenStudy (helder_edwin):

you got the same slope! but this line goes from left to right. do you think this is right?

OpenStudy (helder_edwin):

anyway. let' check \[ \Large m_2=\frac{3-0}{0-0.75}=\frac{3}{-0.75}=-4 \]

OpenStudy (anonymous):

y-7.5=-4(x-0)

OpenStudy (helder_edwin):

almost \[ \Large y-0.75=-4x \]

OpenStudy (anonymous):

Ok so how do you make the equation ?

OpenStudy (helder_edwin):

these are the equations! but, do they look the same as in your problem?

OpenStudy (anonymous):

No they don't relate to the answer choices.

OpenStudy (helder_edwin):

so we turn our equations into the form you were given!

OpenStudy (helder_edwin):

we first had: \[ \Large y+3=0.4x=\frac{2}{5}x \] so multiply by 5 and get \[ \Large 5y+15=2x \] rearranging \[ \Large 2x-5y=15 \] right?

OpenStudy (helder_edwin):

do the same with the second! \[ \Large y-0.75=-4x \] remember \[ \Large 0.75=\frac{3}{4} \]

OpenStudy (anonymous):

Will the answer be a

OpenStudy (helder_edwin):

i dont know!

OpenStudy (helder_edwin):

you have some symbols missing \[ 2x-5y\ ?\ 15 \]

OpenStudy (helder_edwin):

let's try something easier! i hope you got something of everything we did!

OpenStudy (helder_edwin):

choose a point in the green region of your picture (the green region is where the yellow and blue regions meet).

OpenStudy (anonymous):

Ok and yes I did thanks for helping me a little .

OpenStudy (helder_edwin):

choose a point, say \[ \Large (x,y)=(5,-5) \]

OpenStudy (helder_edwin):

OK?

OpenStudy (helder_edwin):

listen, i have to go 4 a while! replace the point you chose into the sets of equations you have and you'll get the answer!

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