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Mathematics 24 Online
OpenStudy (theviper):

Please help:)

OpenStudy (anonymous):

with what??!?!?!?!!?

OpenStudy (theviper):

If\[a^x=b^y=c^z \]& \[b^2=ac,\]then\[\frac{1}{x}+\frac{1}{z}=?\]

OpenStudy (theviper):

@lgbasallote @mathslover @Hero @UnkleRhaukus @waterineyes Plz help:)

mathslover (mathslover):

wait

OpenStudy (anonymous):

3/2?

mathslover (mathslover):

Did u try to put b^2=ac in that expression ?

OpenStudy (theviper):

Sorry but the ans is\[\Huge{\frac{2}{y}}\]

OpenStudy (theviper):

Can I have the full ans plz becoz I have no idea a bout this question:(

mathslover (mathslover):

Ok @waterineyes please dont answer i want to try it first : D

OpenStudy (theviper):

LOL

mathslover (mathslover):

I got it wait let me post it

OpenStudy (theviper):

k

OpenStudy (anonymous):

This is a trick question

OpenStudy (theviper):

let us see Kushaswa Ravi Shrimali answer

mathslover (mathslover):

let a^x=b^y=c^z=k

OpenStudy (anonymous):

Yeah then??

mathslover (mathslover):

wait

mathslover (mathslover):

OpenStudy (theviper):

such a simple way to solve I didn't see thank u @mathslover deserves a medal:)

mathslover (mathslover):

\[\huge{a^x=b^y=c^z=k}\] \[\huge{a^x=k}\] \[\huge{a=k^{\frac{1}{x}}}\] \[\huge{a^x=b^y}\] \[\huge{b^y=k^1}\] \[\huge{k^{\frac{1}{x}*y}=k^1}\] \[\huge{\frac{y}{x}=1}\] \[\huge{x=y}\] \[\huge{\frac{1}{x}+\frac{1}{y}=\frac{1}{y}+\frac{1}{y}=\frac{2}{y}}\]

mathslover (mathslover):

BEST OF LUCK FOR NTSE !

OpenStudy (theviper):

tum itni jaldi itna bada kaise likhte ho koi short trick hai??

OpenStudy (anonymous):

@mathslover we have to find 1/x + 1/z..

OpenStudy (theviper):

Thanx! but tumhe kaise pata chala ki ye /NTSE ka ques hai

OpenStudy (anonymous):

Sorry the answer will be 2/y.. My mistake..

mathslover (mathslover):

No problem

OpenStudy (theviper):

thanx @waterineyes @mathslover :)

mathslover (mathslover):

Ur welcome and I know about NTSE as i had done these all questions :)

OpenStudy (theviper):

of X also??

OpenStudy (anonymous):

\[\huge a^x = b^y\] \[\implies \huge a = b^{\frac{y}{x}}\] \[\huge c^z = b^y\] \[\implies \huge c = b^{\frac{y}{z}}\] \[\huge b^2 = ac\] \[\huge b^2 = (b)^{\frac{y}{x}} \times (b)^{\frac{y}{z}}\] \[\huge 2 = \frac{y}{x} + \frac{y}{z}\] \[\huge \frac{1}{x} + \frac{1}{z} = \frac{2}{y}\]

OpenStudy (theviper):

tenth ke bhi kiye hai??

OpenStudy (theviper):

@mathslover

mathslover (mathslover):

Yes i have tried ..@TheViper Please type in english here . so that other users can also understand that all

OpenStudy (theviper):

k!

OpenStudy (theviper):

of Biology?

mathslover (mathslover):

NOT AT ALL :D

OpenStudy (theviper):

I wanna do Physics, Chemistry & Mathematics:)

OpenStudy (theviper):

Are u intelligent at Chem ??? Kushaswa Ravi Shrimali @mathslover

mathslover (mathslover):

I think i am at least at a level of 10

OpenStudy (theviper):

!!!!!!!!

OpenStudy (theviper):

\[\LARGE{\color{blue}{\text{Best Of Luck for your bright future!!}}}\]

OpenStudy (theviper):

Now-a-days u dony reply my messages @mathslover :(

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