Mathematics
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OpenStudy (theviper):
Please help:)
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OpenStudy (anonymous):
with what??!?!?!?!!?
OpenStudy (theviper):
If\[a^x=b^y=c^z \]& \[b^2=ac,\]then\[\frac{1}{x}+\frac{1}{z}=?\]
OpenStudy (theviper):
@lgbasallote @mathslover @Hero @UnkleRhaukus @waterineyes Plz help:)
mathslover (mathslover):
wait
OpenStudy (anonymous):
3/2?
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mathslover (mathslover):
Did u try to put b^2=ac in that expression ?
OpenStudy (theviper):
Sorry but the ans is\[\Huge{\frac{2}{y}}\]
OpenStudy (theviper):
Can I have the full ans plz becoz I have no idea a bout this question:(
mathslover (mathslover):
Ok @waterineyes please dont answer i want to try it first : D
OpenStudy (theviper):
LOL
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mathslover (mathslover):
I got it wait let me post it
OpenStudy (theviper):
k
OpenStudy (anonymous):
This is a trick question
OpenStudy (theviper):
let us see Kushaswa Ravi Shrimali answer
mathslover (mathslover):
let a^x=b^y=c^z=k
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OpenStudy (anonymous):
Yeah then??
mathslover (mathslover):
wait
mathslover (mathslover):
OpenStudy (theviper):
such a simple way to solve I didn't see thank u @mathslover
deserves a medal:)
mathslover (mathslover):
\[\huge{a^x=b^y=c^z=k}\]
\[\huge{a^x=k}\]
\[\huge{a=k^{\frac{1}{x}}}\]
\[\huge{a^x=b^y}\]
\[\huge{b^y=k^1}\]
\[\huge{k^{\frac{1}{x}*y}=k^1}\]
\[\huge{\frac{y}{x}=1}\]
\[\huge{x=y}\]
\[\huge{\frac{1}{x}+\frac{1}{y}=\frac{1}{y}+\frac{1}{y}=\frac{2}{y}}\]
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mathslover (mathslover):
BEST OF LUCK FOR NTSE !
OpenStudy (theviper):
tum itni jaldi itna bada kaise likhte ho
koi short trick hai??
OpenStudy (anonymous):
@mathslover we have to find 1/x + 1/z..
OpenStudy (theviper):
Thanx! but tumhe kaise pata chala ki ye /NTSE ka ques hai
OpenStudy (anonymous):
Sorry the answer will be 2/y..
My mistake..
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mathslover (mathslover):
No problem
OpenStudy (theviper):
thanx @waterineyes @mathslover :)
mathslover (mathslover):
Ur welcome and I know about NTSE as i had done these all questions :)
OpenStudy (theviper):
of X also??
OpenStudy (anonymous):
\[\huge a^x = b^y\]
\[\implies \huge a = b^{\frac{y}{x}}\]
\[\huge c^z = b^y\]
\[\implies \huge c = b^{\frac{y}{z}}\]
\[\huge b^2 = ac\]
\[\huge b^2 = (b)^{\frac{y}{x}} \times (b)^{\frac{y}{z}}\]
\[\huge 2 = \frac{y}{x} + \frac{y}{z}\]
\[\huge \frac{1}{x} + \frac{1}{z} = \frac{2}{y}\]
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OpenStudy (theviper):
tenth ke bhi kiye hai??
OpenStudy (theviper):
@mathslover
mathslover (mathslover):
Yes i have tried ..@TheViper Please type in english here . so that other users can also understand that all
OpenStudy (theviper):
k!
OpenStudy (theviper):
of Biology?
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mathslover (mathslover):
NOT AT ALL :D
OpenStudy (theviper):
I wanna do Physics, Chemistry & Mathematics:)
OpenStudy (theviper):
Are u intelligent at Chem ???
Kushaswa Ravi Shrimali
@mathslover
mathslover (mathslover):
I think i am at least at a level of 10
OpenStudy (theviper):
!!!!!!!!
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OpenStudy (theviper):
\[\LARGE{\color{blue}{\text{Best Of Luck for your bright future!!}}}\]
OpenStudy (theviper):
Now-a-days u dony reply my messages @mathslover :(