Question

Please help :X

Find theta in radians if 0 ≤ theta ≤ 2 pi and tan square theta = 1/3

Answer 1

May be some one help you :soon
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Answer 2

if
\[\tan ^2 (\theta) = \frac{1}{3}\]

then

\[\tan(\theta) = \pm \frac{1}{\sqrt{3}}\]

Answer 3

thank u :)

Answer 4

the value of

\[\tan^{-1}(\frac{1}{\sqrt{3}}) = \frac{\pi}{6}\]

so there is an angle in every quadrant to find them just complete the calculations below

so first quadrant the answer is above

2nd quadrant its

\[\pi - \frac{\pi}{6}\]

3rd quadrant

\[\pi + \frac{\pi}{6}\]

4th quadrant

\[2\pi - \frac{\pi}{6}\]